服工—字典

第一题:

aDict = {'1':'Mon','2':'Tue','3':'Wed','4':'Thu','5':'Fri',

         '6':'Sat','7':'Sun'}

a = input()

b = aDict.get(a)

print(b)

第二题:

aDict = dict()

while(True):

    s = input().split(':')

    if s == ['']:

        break

    aDict[s[0]] = s[1]

s = input('请输入要查询的课程：\n')

try:

    print(aDict[s])

except:

    print('没有该门课程')

思考:列表下标的索引,split()返回序列!!!,抛出异常

第三题:

s1 = input().split()

s2 = input().split()

aDict = {}

for i in range(len(s1)):

    aDict[s1[i]] = s2[i]

temp = sorted(aDict.keys())

result = []

for j in temp:

    result = result + [(j,aDict[j])]

print(result)

第四题：

data = list(map(int,input().split(',')))

goal = int(input())

flag = False

for i in range(len(data)):

    for j in range(i+1,len(data)):

        if(data[i]+data[j] == goal):

            print('{} {}'.format(i,j))

            flag = True

if (flag == False) :

    print('no answer')

    

第五题:待解决

oDict = eval(input())

tDict = eval(input())

one = set(oDict.keys())

two = set(tDict.keys())

one.update(two)

keys = sorted(one)

values = []

for i in keys:

    temp = oDict.get(i)+tDict.get(i)

    values.append(temp)

result = dict(zip(keys,values))

方式二:

oDict = eval(input())

temp = oDict.copy()

tDict = eval(input())

oDict.update(tDict)

for i in oDict:

    if i in temp and i in tDict:

        oDict[i] = temp[i] + oDict[i]

keys = list(oDict.keys())

keys.sort()

result = {}

for i in keys:

    result[i] = oDict.get(i)

print(result)

第六题:

s = input()

aSet = set(s)

aDict = {}

for i in s:

    aDict[i] = s.count(i)

aList = list(aDict.items())

aList.sort(key = lambda x:x[1],reverse = True)

for i in aList:

    print('{} : {}'.format(i[0],i[1]))

思考:for i in s为了保证输出的原来序列,放入的时候按顺序放,因而先for i in aSet错误!!!